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Power Set (All Subsets)

Backtracking
O(2^n) time, O(2^n) space
Intermediate

Generate all possible subsets of a set. Total 2^n subsets for n elements. Classic backtracking problem.

Visualization

Interactive visualization for Power Set (All Subsets)

Power Set Generation

• Time: O(2^n × n)

• Space: O(2^n × n)

• Generates all 2^n subsets

Interactive visualization with step-by-step execution

Implementation

Language:
1function subsets(nums: number[]): number[][] {
2  const result: number[][] = [];
3  
4  const backtrack = (index: number, current: number[]): void => {
5    result.push([...current]);
6    
7    for (let i = index; i < nums.length; i++) {
8      current.push(nums[i]);
9      backtrack(i + 1, current);
10      current.pop();
11    }
12  };
13  
14  backtrack(0, []);
15  return result;
16}
17
18// Bit manipulation approach
19function subsetsBitMask(nums: number[]): number[][] {
20  const result: number[][] = [];
21  const n = nums.length;
22  
23  for (let mask = 0; mask < (1 << n); mask++) {
24    const subset: number[] = [];
25    for (let i = 0; i < n; i++) {
26      if (mask & (1 << i)) {
27        subset.push(nums[i]);
28      }
29    }
30    result.push(subset);
31  }
32  
33  return result;
34}

Deep Dive

Theoretical Foundation

For each element, make two recursive choices: include it or exclude it. Builds solution tree with 2^n leaves. Can also use bit manipulation or iterative approach.

Complexity

Time

Best

O(2^n)

Average

O(2^n)

Worst

O(2^n)

Space

Required

O(2^n)

Applications

Use Cases

Combinatorics
Feature selection
Set operations

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Combination Sum

Find all unique combinations in array where chosen numbers sum to target. Numbers can be reused. Classic backtracking problem with pruning optimization.

Backtracking

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Backtracking
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