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Combination Sum

Backtracking
O(2^t) where t=target time, O(t) recursion depth space
Intermediate

Find all unique combinations in array where chosen numbers sum to target. Numbers can be reused. Classic backtracking problem with pruning optimization.

Prerequisites:
Backtracking
Recursion
Array manipulation
Sorting algorithms

Visualization

Interactive visualization for Combination Sum

Combination Sum

• Backtracking with reusable elements

• Pruning when sum > target

• Classic subset generation problem

Interactive visualization with step-by-step execution

Implementation

Language:
1function combinationSum(candidates: number[], target: number): number[][] {
2  const result: number[][] = [];
3  const current: number[] = [];
4  candidates.sort((a, b) => a - b);
5  
6  function backtrack(start: number, remaining: number): void {
7    if (remaining === 0) {
8      result.push([...current]);
9      return;
10    }
11    
12    for (let i = start; i < candidates.length; i++) {
13      if (candidates[i] > remaining) break; // Pruning
14      
15      current.push(candidates[i]);
16      backtrack(i, remaining - candidates[i]); // Can reuse same element
17      current.pop();
18    }
19  }
20  
21  backtrack(0, target);
22  return result;
23}
24
25// Combination Sum II (no duplicates, each number used once)
26function combinationSum2(candidates: number[], target: number): number[][] {
27  const result: number[][] = [];
28  const current: number[] = [];
29  candidates.sort((a, b) => a - b);
30  
31  function backtrack(start: number, remaining: number): void {
32    if (remaining === 0) {
33      result.push([...current]);
34      return;
35    }
36    
37    for (let i = start; i < candidates.length; i++) {
38      if (i > start && candidates[i] === candidates[i - 1]) continue; // Skip duplicates
39      if (candidates[i] > remaining) break;
40      
41      current.push(candidates[i]);
42      backtrack(i + 1, remaining - candidates[i]); // Move to next
43      current.pop();
44    }
45  }
46  
47  backtrack(0, target);
48  return result;
49}

Deep Dive

Theoretical Foundation

Explore all combinations by trying each candidate, recursing with reduced target. Backtrack when target becomes negative or zero. Sort array and prune when current candidate exceeds remaining target.

Complexity

Time

Best

O(2^t)

Average

O(2^t)

Worst

O(2^t)

Space

Required

O(t) recursion depth

Applications

Industry Use

1

Coin change problem variations

2

Subset sum and partition problems

3

Resource allocation with constraints

4

Knapsack problem variants

5

Budget planning and optimization

6

Recipe ingredient combinations

7

Investment portfolio selection

Use Cases

Subset sum variants
Coin change combinations
Partition problems

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