Palindrome Partitioning (All)
Partition string such that every substring is palindrome. Return all possible partitions using backtracking.
Visualization
Interactive visualization for Palindrome Partitioning (All)
Palindrome Partitioning:
- • Backtracking to find all partitions
- • Each part must be palindrome
Interactive visualization with step-by-step execution
Implementation
1function partition(s: string): string[][] {
2 const result: string[][] = [];
3 const current: string[] = [];
4
5 function isPalindrome(str: string, left: number, right: number): boolean {
6 while (left < right) {
7 if (str[left++] !== str[right--]) return false;
8 }
9 return true;
10 }
11
12 function backtrack(start: number): void {
13 if (start === s.length) {
14 result.push([...current]);
15 return;
16 }
17
18 for (let end = start; end < s.length; end++) {
19 if (isPalindrome(s, start, end)) {
20 current.push(s.substring(start, end + 1));
21 backtrack(end + 1);
22 current.pop();
23 }
24 }
25 }
26
27 backtrack(0);
28 return result;
29}Deep Dive
Theoretical Foundation
For each position, try all possible palindromic substrings starting from that position. Recursively partition remaining string. Time: O(n × 2^n) - 2^n partitions, O(n) to check palindrome and copy.
Complexity
Time
O(n × 2^n)
O(n × 2^n)
O(n × 2^n)
Space
O(n)
Applications
Industry Use
Text processing and analysis
String segmentation problems
Natural language processing
DNA sequence analysis
Compression algorithm preprocessing
Pattern recognition in strings
Linguistic analysis tools
Use Cases
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